C. I, II, and III
I’m sure it’s the answer not positive though, I’m sorry.
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
538.3
Step-by-step explanation:
First of all find the area of the rectangle
L*W
15*30
450
Now find the area of semi circle
1/2
Since radius is half a diameter divided 15 by 2=7.5
1/2
7.5 times 7.5= 56.25
1/2*3.14*56.25
56 times 3.14 is 176.625 now multiply 176.625 by 1/2
Answer is 88.3125
Now add 450 to 88.3125
Final answer: 538.3125
60% decimal = .6 fraction= 6/10
3/4 percent =75% (think of $$) decimal =.75
0.23 percent =23% fraction= 23/100
1/8 percent= 12.5 decimal = 0.125
18% decimal= .18 fraction= 18/100 (simplified to 9/50)
2/3 percent=0.6% repeating (so put a line over 6) decimal= 0.6 repeating aswell so do the same as last
Your welcome :)
Answer:
A. DEF=EDF
Step-by-step explanation:
