Consecutive integers are 1 apart
they are
x,x+1,x+2
the sum of their squares is 194
x²+(x+1)²+(x+2)²=194
expand
x²+x²+2x+1+x²+4x+4=194
x²+x²+x²+2x+4x+1+4=194
3x²+6x+5=194
minus 5 from both sides
3x²+6x=189
3(x²+2x)=189
divide both sides by 3
x²+2x=63
minus 63 from bot sides
x²+2x-63=0
what 2 numbers multiply to get -63 and add to get 2
-7 and 9
(x-7)(x+9)=0
set each to zero
x-7=0
x=7
x+9=0
x=-9
for x=7
x+1=8
x+2=9
for x=-9
x+1=-8
x+2=-7
the integers are 7,8,9 or -9,-8,-7
Answer: y=-4x+2
Step-by-step explanation: Move all terms not containing Y to the right side of the equation.
Answer:
-7y+8x
Step-by-step explanation:
-2y-x-5y+9x
That would be
10x > 4x - 2
