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3 years ago

What is the sum of 3.6 × 103 and 6.1 × 103? Answer Choices 9.7x10^3 9.7x10^6 97x10^3 97x10^6

Mathematics

1 answer:

Nutka1998 [239]3 years ago

4 0

Answer:

9.7×10³

Step-by-step explanation:

(3.6×10³) + (6.1×10³) = (3.6+6.1)×10³ = 9.7×10³

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The factor of 10³ can be factored out while you do the sum.

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A calculator can find the sum for you. A scientific or graphing calculator will have the option to display the result in scientific notation format.

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A rectangular lot that measures 150 ft by 200 ft is completely fenced. What is the approximate length, in feet, of the fence?

Ivenika [448]

300,000 because you have to just multiply 150 by 200

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3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago

Select all the equations that have x = 0.9 as a solution

Solnce55 [7]

C and d are going to be the answers to your question. >-< :)

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3 years ago

The length of a rectangular field is 4 meters less than 5 times the breadth of the hall. What is the length, if the breadth is b

vlabodo [156]

IF BREADTH=b meters
THEN LENGTH=4 meter less than 3 times than the breadth of the hall.
LENGTH=3b-4 meters
the length of the rectangular hall is=3b-4 meters

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2 years ago

Find the third side in simplest radical form

klasskru [66]

Answer:

$2 \sqrt{71} \: units$

Step-by-step explanation:

Given is a right angled triangle in which third side is the hypotenuse.

Therefore, by Pythagoras theorem:

$thid \: side = \sqrt{ {15}^{2} + ( \sqrt{59} )^{2} } \\ \\ = \sqrt{225 + 59} \\ \\ = \sqrt{284} \\ \\ = \sqrt{ {2}^{2} \times 71 } \\ \\ = 2 \sqrt{71} \: units$

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3 years ago