R(t) = integral of r'(t) = integral of ti + e^tj + te^tk = 1/2t^2i + e^tj + (te^t - e^t)k + c
r(0) = j - k + c = i + j + k
c = i + 2k
Therefore, r(t) = (1/2t^2 + 1)i + e^tj + (te^t - e^t + 2)k
Answer:
19
Step-by-step explanation:
1. y= -5x + 12
y= -5x – 7
2. -5x + 12
-(-5x – 7)
3. -5x + 12
<u>5x + 7</u>
0 +19
4. 19
sorry i cant solve this problem
maybe next time
hope you understand me!
Given:
principal: 5,500
term: 4 years
interest rate: 4.8% per annum
early wdl of 475
penalty is the 3 months interest of the amount withdrawn.
Interest = 475 * 4.8% * 3/12
Interest = 475 * 1.2%
interest = 5.7 is the amount of the penalty
Answer:
-65 i suppose
Step-by-step explanation:
