Answer:
so idc![\sqrt[n]{x} \sqrt{x} \alpha \pi x^{2} \\ \left \{ {{y=2} \atop {x=2}} \right. x_{123} \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%5Csqrt%7Bx%7D%20%5Calpha%20%5Cpi%20x%5E%7B2%7D%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x_%7B123%7D%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D)
443
Step-by-step explanation: its 2 6\7
Answer:
A: 2/3
Step-by-step explanation:
Answer:
D) V= 1/6 bh
Step-by-step explanation:
The expression that provides the volume of the pyramid is as follows;
As mentioned in the question
It is given that the pyramid put inside a prism
Also the pyramid contains the similar base area but the height is half of the prism
so the base area of the pyramid is b
And, the Height of the pyramid = h ÷ 2
Now as we know that
The volume of the pyramid is
V = 1 ÷3 × base ares × height
= 1 ÷ 3 × b × h ÷ 2
V = 1 ÷ 6 bh
So, the volume is 1 ÷6 bh cube unit.
Answer:
HUH? WHAT?
Step-by-step explanation:
