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Genrish500 [490]
2 years ago
10

What is the slope of the line through the points (-4, 2) and (-16, -6)?

Mathematics
2 answers:
Blababa [14]2 years ago
8 0

Answer:

The slope is equal to \frac{2}{3} . So the right answer is A.

Step-by-step explanation:

We know that if we are given to points of a function we can find out its slope by using the following formula....

m = \frac{y_{2}-y_{1} }{x_{2}-x_{1}  }

Where m is the slope,  x_{1} and y_{1} are the coordinates of the first point, x_{2} and y_{2} are coordinates of the second point.

Let (-4, 2) be (x_{1} , y_{1})

Let (-16, - 6) be (x_{2}, y_{2} )

then......

Effectus [21]2 years ago
7 0

Answer:

A: 2/3

Step-by-step explanation:

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How would logx (49) = x look like in exponential form
Ivanshal [37]

I'm assuming the given log equation is \log_{\text{x}}(49) = \text{x}

If so, then the exponential form is \text{x}^{\text{x}} = 49

This is because the general form \log_{\text{b}}(\text{x}) = \text{y} transforms into \text{y} = \text{b}^{\text{x}}

For both equations, the 'b' is the base.

5 0
2 years ago
Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in
kiruha [24]

Answer:

Average rate of change of function is -2.

Step-by-step explanation:

Given f(x)=\frac{-1}{4}(x+4)^2-8.

we have to find the average rate of change for the quadratic function from x=−2 to x = 2.

f(-2)=\frac{-1}{4}(-2+4)^2-8=\frac{-1}{4}(4)-8=-9

f(2)=\frac{-1}{4}(2+4)^2-8=\frac{-1}{4}(36)-8=-17

The average rate of change of the function  f(x) on interval [-2,2] is

\frac{f(b)-f(a)}{b-a}=\frac{f(2)-f(-2)}{2-(-2)}=\frac{-17-(-9)}{4}=\frac{-8}{4}=-2

3 0
3 years ago
PLEASE HELP 17 points
Ksivusya [100]

Answer: I say B its a bit hard but i think i got it not  sure but Good Luck!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which of the following linear relationships is NOT also a proportional relationship?
katen-ka-za [31]

The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  .

A linear relationship in the form of y = mx + c is said to be a proportional relationship when c = 0  .

in the question

Part(a)

the equation is  y = (2)x - 3

on comparing it with y = mx + c , we get c = -3 , which is not 0 .

So , it is not a proportional relationship .

Part(b)

the equation is  y = (-2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(c)

the equation is  y = (3/5)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(d)

the equation is  y = - (1/2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Therefore, The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  , that are options (b) , (c) and (d) .

The given question is incomplete , the complete question is

Which of the following linear relationships is NOT also a proportional relationship?

(a) y = (2)x - 3

(b) y = (-2)x

(c) y = (3/5)x

(d) y = - (1/2)x

Learn more about Proportionality here

brainly.com/question/14967814

#SPJ1

8 0
1 year ago
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