The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
y ≥ -x +2
Step-by-step explanation:
The solid line has a slope of -1 and a y-intercept of 2, so its equation in slope-intercept form is ...
y = -x +2
The shaded area is above this line, and the line is part of the solution set, so we want an inequality that has "y" and the comparison symbol in this order: "y ≥" or "≤ y".
We already have an equation with "y" on the left, above, so we just need to introduce the comparison symbol:
y ≥ -x +2
Another way to write this is ...
x + y ≥ 2
Answer:
C
Step-by-step explanation:
I think you have to call a = 14/32 and b = 7/4
3a = 3 * 14/32 = 42/32
b = 1 3/4 = (4 + 3)/4 = 7/4
42/32 // 7/4 Invert and multiply
42/32 * 4/7 Cancel 4 into 32 and 7 into 42
6/8 = 3/4
I make the answer C
Answer:
31
Step-by-step explanation:
50 x .62= 31
(games played) x the percentage won.
You could muliply 50 by 62% if your calculator has the % symbol if not you have to turn it into a decimal. To go from percent to decimal just take your percentage and move the decimal to the left twice. 62% = .62
