Question

What are the solutions to the quadratic equation below? X^2-8x+16

Answer 1

Answer:

x=4*

Step-by-step explanation:

*THIS IS ASSUMING THAT THIS EQUATION IS EQUAL TO ZERO

X^2-8x+16=0

Let's solve this equation by factoring. First, we need to find factors of 16 that add to -8. We find that those factors are -4 and -4. X^2 is simply x times x.

Therefore, when it is factored It should look like this:

(x-4)(x-4)=0

Now we take both factors and set them equal to zero:

x-4=0; x-4=0

In both of these equations we just need to add 4 to both sides.

x=4; x=4

x=4

HTH :)

Answer 2

(₋4)²

how i got it -

1st i used the sum-product pattern

x² - 8x + 16

x² -4-4+16

then, found the common fact from the two pairs

x² - 4 - 4 + 16

(-4) - 4(-4)

rewrite in factored form

(x-4)-4(-4)

(-4) (-4)

combine to a square

(-4) (-4)