1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
When the image of point C is reflected across the line, then it's written as C'.
- - To find a "what number is x% of x"
You have to first change 35% into a decimal.
35%=0.35
Now 0.35*22=7.7
Therefore your final answer is 7.7
Answer:
Choice C
Step-by-step explanation:
A and B represent symmetric distributions, that is most data values lie in the middle and the both tails are equally longer.
C represents a positively skewed distribution, most of the data values lie to the left with a few points skewing the shape of the distribution to the right.
So 1/2 for the Coin and 2/6 or 1/3 for the Coin
So you need to add them
1/2 + 1/3
you'll multiple the Numerators and denominators
1x1= 1
2x3= 6
Answer: So you have 1/6 chance of flipping a Coin on heads and also rolling 5 or greater on a dice :)
