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Alenkasestr [34]

3 years ago

8

What actions did colonists take to protest the Townshend Acts?

1 answer:

brilliants [131]3 years ago

8 0

Answer:

The Townshend Acts would use the revenue raised by the duties to pay the salaries of colonial governors and judges, ensuring the loyalty of America's governmental officials to the British Crown. However, these policies prompted colonists to take action by boycotting British goods.

-Hope this helps :)

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77julia77 [94]

Answer:

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Step-by-step explanation:

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2 years ago

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What are values of X mean in maths

GaryK [48]

Answer:

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown".

Step-by-step explanation:

In x + 2 = 7, x is a variable, but we can work out its value if we try:)

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2 years ago

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What is the slipe of (-1,3) and (1,3) ?

Minchanka [31]

Answer:

0 theres no slope lol cause

3-3= 0

1--1=2

7 0

3 years ago

Any help please? For extra credit

Law Incorporation [45]

Answer:

see explanation

Step-by-step explanation:

(a)

A recursive formula allows any term in the sequence to be found by adding the common difference d to the previous term.

Here d = - 4 , then recursive formula is

$a_{n}$ = $a_{n-1}$ - 4 with a₁ = 2

(b)

The explicit formula for an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = - 4, thus

$a_{n}$ = 2 - 4(n - 1) = 2 - 4n + 4 = 6 - 4n ← explicit formula

(c)

Using the recursive formula

a₁ = 2

a₂ = 2 - 4 = - 2

a₃ = - 2 - 4 = - 6

Using the explicit formula

a₅ = 6 - 4(5) = 6 - 20 = - 14

a₁₀ = 6 - 4(10) = 6 - 40 = - 34

a₁₀₀ = 6 - 4(100) = 6 - 400 = - 394

4 0

2 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

2 years ago