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2 years ago

I kinda need help with this i’ve already done all the other questions but this one and i really want these 600 points :( <3

Mathematics

1 answer:

lawyer [7]2 years ago

6 0

I think that the answer is A, because in the range, none of the numbers should be the same, and the numbers are all different in choice A

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Prefixes, roots, and suffixes are examples of _____

mojhsa [17]

Answer:

The correct answer should be : Word parts

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the magnitude of AB. A(-2, 6), B(1, 10) O A 2 OB. ✔️15 O C.5 OD ✔️2

natita [175]

Answer:

C. 5

Step-by-step explanation:

Use the Distance Formula.

Substitute the values of x1 , y1 , x2 , and y2 .

|AB|² =|(1--2)²+(10-6)²|

|AB|² = |9+16|

|AB| = √ 25

|AB| =5

6 0

3 years ago

Rosa and Albert receive the same amount of allowance each week . The table shows what part of their allowance they each spent on

Anettt [7]

1/2 x > 0.4x

where Robert's spending is greater than Rosa's spending.

Allowance of Rosa = Allowance of Robert

let x = allowance

Rosa : video games = 0.4(x) ; pizza = 2/5 (x)
Robert : video games = 1/2 (x) ; pizza = 0.25 (x)

let us assume that their allowance is 100 each week. so, x = 100

Rosa : video games = 0.40(100) = 40
pizza 2/5 (100) = 200/5 = 40
total spending: 40 + 40 = 80

Robert : video games = 1/2 (100) = 50
pizza 0.25 (100) = 25
total spending: 50 + 25 = 75

Spending on video games
Rosa = 40
Robert = 50

Robert spent more of his allowance on video games than Rosa.

1/2 x > 0.4x

7 0

3 years ago

What is the SCALE FACTOR? What type of DILATION is occurring from the first triangle to the second triangle?

REY [17]

Answer:

Step-by-step explanation:

$\frac{1,5}{6} = 0,25 = \frac{25}{100} = 1:4$

7 0

2 years ago

A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline

dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So $P(B) = 0.35$

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

$P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125$

Probability

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667$

46.67% probability that they flew with airline B.

5 0

3 years ago