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4 years ago

I need help with this question

Mathematics

1 answer:

mr Goodwill [35]4 years ago

5 0

Answer:

It would be 1.5m+4 is greater than or equal to 7. This is because 1.5m is the regular rate of growth, plus the 4cm already grown. She wants the hair to be no shorter than 7cm. So, the 15m+4 has to be greater than the 7cm.

Step-by-step explanation:

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Two lines intersect. Find the value of b and c.<br><br>Solution:

loris [4]

Answer:

B=42° and C=138°

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLZ HELPPP THIS IS DUE TORR

Mademuasel [1]

Minimum=25
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5 0

3 years ago

max and his friend eke are comparing their ages. They figure out that if they double max's age from 3 years ago and add it to ze

Lapatulllka [165]

Answer:

Max is currently 12 years old.

Step-by-step explanation:

Zeke's current age = 8 years

Lets take Max's current age as $x$ years.

Then Max's age 3 years ago = $x-3$

Double Max's age 3 years ago = $2*(x-3)$

Double Max's age 3 years ago + Zee's current age = 26

⇒ $2*(x-3)$ + $8$ = $26$

= $2*(x-3)+8=26$

= $2x-6+8=26$ (Simplifying the brackets)

= $2x+2=26$

= $2x+2-2=26-2$ $2x=24=$ $x=12$

So Max's current age is 12 years.

5 0

3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$