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3 years ago

I need help with this question

Mathematics

1 answer:

mr Goodwill [35]3 years ago

5 0

Answer:

It would be 1.5m+4 is greater than or equal to 7. This is because 1.5m is the regular rate of growth, plus the 4cm already grown. She wants the hair to be no shorter than 7cm. So, the 15m+4 has to be greater than the 7cm.

Step-by-step explanation:

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The measure of the hypotenuse is? (side c)

Sliva [168]

Answer: 25
explanation:
7² + 24² = c²
49 + 576 = c²
625 = c²
c = √625
c= 25

or just know some pythagorean triples

4 0

3 years ago

Read 2 more answers

LaTonda rolls two number cubes that are each numbered 1 through 6. What is the probability that the sum of the numbers on the to

ZanzabumX [31]

Answer:

1/4

Step-by-step explanation:

The maximum sum of the two cubes is 6 + 6 = 12

The multiples of 4 until 12 are: 4, 8 and 12.

each cube has 6 possible values, so two cubes have a total of 6 * 6 = 36 possible results

We can have a sum of 4 with the pairs (1,3), (2,2), (3,1).

We can have a sum of 8 with the pairs (2,6), (3,5), (4,4), (5,3), (6,2)

We can have a sum of 12 with the pair (6,6)

So we have a total of 9 pairs that satisfy our condition over a total of 36 possibilities, so the probability is 9 / 36 = 1/4

8 0

3 years ago

A geometric sequence has these properties: a^1=2

grin007 [14]

The third term of the sequence is 20

3 0

3 years ago

Law of Sines or Law of Cosines....Help!!

iren2701 [21]

Answer:

Law of cosines to find missing measures

c^2= a^2+ b^2 - 2ab*cos(C)

Used because it is a SAS triangle

Step-by-step explanation:

This is known as a side, angle, side, or SAS triangle. We can find the missing measures by using the Law of cosines

c^2= a^2+b^2-2ab*cos(C)

7 0

3 years ago

Determine the equation for the quadratic relationship graphed below.

kap26 [50]

Answer:

$\large \boxed{\sf \bf \ \ y=3x^2-6x-1 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

We can read from the graph that the vertex is (1,-4) , it means that the equation is, a being a real number.

$y=a(x-1)^2-4$

And the point (0,-1) is on the graph so we can write.

$a\cdot 1^2-4=-1 \\\\a-4+4=-1+4\\\\a = 3$

So the equation is.

$y=3(x-1)^2-4\\\\=3(x^2-2x+1)-4\\\\=3x^2-6x+3-4\\\\=3x^2-6x-1\\\\=\boxed{3}x^2\boxed{-6}x\boxed{-1}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago