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Temka [501]
3 years ago
13

Maggie creates the fraction models shown to find the value of 1 3/4 divided by 2/3

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer: where is them model

Step-by-step explanation:

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Help i cannot write proportions
Alik [6]

Answer:

example 4:2

Step-by-step explanation:

A proportion shows how many parts of one side equals the other. For every four times i kick a soccer ball, I make it in twice. For every 8 times, I make it in 4.

6 0
2 years ago
What is 15/21 subtracted by 5/7 equal ?
Artemon [7]

Answer:

0

Step-by-step explanation:

<u>Step 1:  Make common denominators</u>

What is the LCM of 21 and 7:  7

So, we need to convert both fractions into a 21 denominator.

<em>15/21 * 1/1 = 15/21</em>

<em>5/7 * 3/3 = 15/21</em>

<em />

<u>Step 2:  Subtract the numbers</u>

15/21 - 5/7 is same as 15/21 - 15/21

15/21 - 15/21

<em>0</em>

<em />

Answer:  0

3 0
3 years ago
Read 2 more answers
Write 0.624 as a percent and as a simplified fraction.
Doss [256]
Okay to find the percent version of 0.624 you multiply by 100. 0.624×100=62.4%. Now as a fraction the last number behind the decimal is in the thousandths place so put 624 over 1000. 624/1000 simplified it would be 78/125
5 0
2 years ago
The difference of 10 and the product of n and 2 is 4 which operation models this​
vagabundo [1.1K]

Answer:

10 - 2n - 4

Step-by-step explanation:

The product of n and 2 is 2n.

Then 10 - 2n is the difference of 10 and the product of n and 2.

In conclusion, we have:  

10 - 2n - 4

3 0
3 years ago
How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
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