Question

Drag the tiles to the correct boxes to complete the pairs.

Answer 1

Answer:

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4} \implies 2^{-32}$

2. $2^4 . (2^2)^{-2} \implies 1$

3. $(-2^{-4}).(2^2)^0 \implies -2^8$

4. $(2^2).(2^3)^{-3} \implies 2^{-5}$

Step-by-step explanation:

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4}$ :

$= \frac{ ( - 2 ^ 2 ) ^ { - 6 } } { ( 2 ^ { - 5 } ) ^ { - 4 } } = \frac{2^{-12}}{2^{20}} = 2^{-12-20}=2^{-32}$

2. $2 ^ 4 . ( 2 ^ 2 ) ^ { - 2 }$ :

$= 2^4 \times \frac{1}{2^4} = 1$

3. $(-2^{-4}).(2^2)^0$ :

$= (-2^4)^2 \times 1 = -2^8$

4. $(2^2).(2^3)^{-3}$ :

$= 2^4 \times \frac{1}{2^9} =\frac{1}{2^5} =2^{-5}$

Answer 2

Answer:

buttcheeck

Step-by-step explanation: