The quadratic equation has two solutions if b^2 - 4ac > 0
Given the equation ax^4 + bx^2 + c=0
Substitute into the formula to have:
The equation becomes aP^2 + bP + c = 0
For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0
learn more on discriminant here; brainly.com/question/1537997
dont know wish i could help you :( sorry i hate when i can't answer a question it makes me feel bad
This problem is very simple. All you have to do is add 10 and 9. The correct answer is D.
Answer:
What equations? there's no picture to reference