There are two possible outcomes of this experiment either success p or failure q. It has a given number of trials and all trials are independent therefore it is<u><em> binomial probability distribution.</em></u>
1- 5 ways
2- 5/16
3- 1/16
4- 1/16
In the question given above n= 5 p =1/2 q= 1/2 r is the given point.
- <u>Part 1:</u>
The number of ways in which different people get off the bus can be calculated using combinations since the order is not essential. Therefore
nCr= 5C4= 5 ways
<u>2. Part 2:</u>
The probability that all four people get off the bus on the first stop is given by :
P (x= 1)= 5C1 (1/2)^0(1/2)^4= 5(1/2)^4= 5/16
<u>3. Part 3:-</u> The probability that all four people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^0(1/2)^4= 1(1/2)^4= 1/16
<u>4. Part 4-</u> The probability that <u><em>exactly three of the four</em></u> people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^3(1/2)^1= 1(1/2)^4= 1/16
For binomial distribution click
brainly.com/question/15246027
brainly.com/question/13542338
You have to remember that 1 equal 100% and that what you need to do is just to multiply the number by 100 and add at the end symbol % .
<span>.0015 * 100 = 0.15% </span>
Answer:
x>3
Step-by-step explanation:
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Answer:
4ti + 5tj + k
Step-by-step explanation:
Initial condition V(0) = k
at t = 0
general equation for v(t )
V(0) = 0i + 0j + c = k
when we compare V(0) and solve for c , c = k
back to general equation
V(t) = 4ti + 5tj + c = 4ti + 5tj + k