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Debora [2.8K]
3 years ago
11

Ryan made $66.50 for mowing 7 lawns on Tuesday. On Wednesday, he made $38 for mowing 4 lawns. Write the proportional relationshi

p in a table and in as a pair of equivalent fractions.

Mathematics
1 answer:
MArishka [77]3 years ago
4 0
66.50 38
——— = ———
7. 4
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Help me with this please
Reika [66]

Answer:

$2,459.21

Step-by-step explanation:

(see attached for reference)

recall that the formula for compound interest is:

A = P [ 1 + (r/n)^ (nt) ]

where,

A = Final amount ( we are asked to find this)

P = principal amount = given as $2,340

r = Annual Interest Rate = given as 5% = 0.05

n = number of times compounded in a year = 4 (compounded quarterly)

t= time = 1 year

Substituting the values into the equation,

A = P [ 1 + (r/n)^ (nt) ]

A = 2,340 [ 1 + (0.05/4)^ (4·1) ]

A = $2,459.21

6 0
2 years ago
Find the slope of the line passing through the points<br> (-4,-3) and (8,-9)
Ilia_Sergeevich [38]
The answer is -1/2

Rise/run
X=run
Y=rise

y2-y1/x2-x1
(-9)-(-3)/(8)-(-4)
-6/12
-1/2

Brainliest my answer if it helped you out?
4 0
3 years ago
1 million + 1 million​
natka813 [3]

Answer: 200,000,000 or 2 million

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
1 year ago
Calculate: 3400*6 1/2 *1/100​
marishachu [46]

questions clear likhh

thank for extra points

7 0
2 years ago
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