Please help solve the system.

What is the approximate value of this logarithmic expression?

Licemer1 [7]

The approximate value of $log_{8}24$ is 1.52832 or 1.53.

What is the logarithmic Expression?

A logarithmic expression is an function that involves the logarithm of an expression containing a variable. To solve exponential equations, first see whether you can write both sides of the equation as powers of the same number.

Here $log_{8}24$ = $log_{2^{3} }24$

= $\frac{1}{3} log_{2}24$

= $\frac{1}{3} log_{2}{8.3}$

= $\frac{1}{3} log_{2}8 + \frac{1}{3} log_{2}3$

= $\frac{1}{3} log_{2}2^3 + \frac{1}{3} log_{2}3$

= $\frac{3}{3} log_{2}2 +\frac{1}{3} log_{2}3$

= $1 + \frac{1}{3} log_{2}3$

= 1 + 0.5283

l $log_{8}24$ ≈ 1.53

The approximate value of $log_{8}24$ is 1.52832 or 1.53.

Learn more about Logarithmic expression from :

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4 0

2 years ago

(50x40÷4+20)+(50÷2+25)

Andru [333]

Answer:= ‌25/2‌x^40+70

6 0

3 years ago

Read 2 more answers

g The total national health expenditures per capita (in dollars) for 2006 and projected to 2021 can be modeled with the equation

Alex73 [517]

Answer:

a) The predicted per capita health expenditures for 2018 is $11943.5.

b) After 2018, it will take 16 years for the 2018 expenditures to double

Step-by-step explanation:

The total national health expenditures per capita, in dollars, is given by the following equation:

$H(t) = 6791e^{0.04343t}$

In which t is the number of years after 2005.

a. Find the predicted per capita health expenditures for 2018.

2018 is 13 years after 2005, so this is H(13).

$H(t) = 6791e^{0.04343t}$

$H(13) = 6791e^{0.04343*13}$

$H(13) = 11943.5$

The predicted per capita health expenditures for 2018 is $11943.5.

b. According to the model, how long will it take the 2018 expenditures to double?

First we find how many years after 2005, in which t is found when H(t) = 2*11943.5.

So

$H(t) = 6791e^{0.04343t}$

$2*11943.5 = 6791e^{0.04343t}$

$e^{0.04343t} = \frac{2*11943.5}{6791}$

$e^{0.04343t} = 3.5174$

Applying ln to both sides

$\ln{e^{0.04343t}} = \ln{3.5174}$

$0.04343t = \ln{3.5174}$

$t = \frac{\ln{3.5174}}{0.04343}$

$t = 29$

It will take 29 years after 2005 = 29-13 = 16 years after 2018.

After 2018, it will take 16 years for the 2018 expenditures to double

5 0

3 years ago

Mark took his family to the movies and spent a total of 78$ on tickets he also bought a soda for each family member each sodas c

AveGali [126]

Answer: He bought about 6 sodas.

Step-by-step explanation:

Given: Tota cost of tickets = $ 78

Cost of each soda = $4.25

Total cost of sodas and tickets = 102.50

Let x = Number of sodas purchased

Then

$78+4.25x=102.50\\\\\Rightarrow\ 4.25x=102.50-78\\\\\Rightarrow\ 4.25x=24.5\\\\\Rightarrow\ x= \dfrac{24.5}{4.25}\\\\\Rightarrow\ x\approx6$

Hence, he bought about 6 sodas.

8 0

3 years ago

In order to answer the following question, please use the following image down below:

Kryger [21]

Answer:

12

Step-by-step explanation:

X^2 = (7+9)(9) -->

X^2 = 16(9) -->

X = 12

8 0

3 years ago