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Ilya [14]
2 years ago
15

How many 16-ounce bottles would be needed to hold the same total amount of water 56 bottles that each holds 20 ounces

Mathematics
1 answer:
snow_lady [41]2 years ago
6 0

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Step-by-step explanation:

Given,

56 bottles hold 20 ounces each.

Total amount 56 bottles hold= 56x20

Total amount hold by 56 bottles= 1120 ounces

Let the number of 16 ounces bottles be = x

Total amount hold by x bottles = 16x

According to the given statement both amounts are same;  

16x=1120\\Dividing\ both\ sides\ by\ 16\\\frac{16x}{16} = \frac{1120}{16} \\x=70

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Keywords: Division, Multiplication

Learn more about division at:

  • brainly.com/question/2035523
  • brainly.com/question/2088305

#LearnwithBrainly

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Solve the equation 3x + 4 = 5x - 8​
CaHeK987 [17]

Answer:

x = 6

Step-by-step explanation:

3x + 4 = 5x - 8

==> add 8 to both sides

in doing so we get 3x + 4 + 8 = 5x - 8 + 8

the -8 and the +8 cancels out and 4 + 8 = 12

we are left with 3x + 12 = 5x

==> subtract 3x from both sides

in doing so we get 3x - 3x + 12 = 5x - 3x

the 3x and -3x cancel out and 5x - 3x = 2x

we are left with 12 = 2x

==> divide both sides by 2

in doing so we get 12/2 which equals 6 and 2x/2x which leaves us with

6 = x

3 0
2 years ago
Read 2 more answers
Are the solutions correct?
Aloiza [94]

Answer:

First one is wrong. x should be 16.

Second one is not completely visible, so cannot say.

Step-by-step explanation:

In the last step, the divison by 4 yields:

x/16 = 1, so x = 16

4 0
2 years ago
Some one please help me on this I am very much dum
AURORKA [14]
I don’t know this one either bro
4 0
2 years ago
Lindsey Wilson was the top scorer in a women's professional basketball league for the 2006 regular season, with a total of 814 p
baherus [9]

Answer:

The number of free throws, two-point throw, and three-point throw are 135, 173, and 111 respectively.

Step-by-step explanation:

Let x,y, and z are the numbers of two-point field goals, numbers of three-point field goals, and the number of free-throws (one-point goal) respectively.

The total points= 814

\Rightarrow 2x+3y+z=814\;\cdots(i)

As the number of two-point  goals was 49 less than double the number of three-point field goals she made.

\Rightarrow x=2y-49 \;\cdots(ii)

Again, the number of free goals was 38 less than the number of two-point field goals she made.

\Rightarrow z=x-38\;\cdots(iii)

From equations (i) and (iii)

2x+3y+x-38=814

\Rightarrow 3x+3y=852

\Rightarrow x+y=284

\Rightarrow 2y-49+y=284 [using equation (ii)]

\Rightarrow 3y=333

\Rightarrow y=111

From equation (ii),

x= 2\times111-38=173

From equation (iii),

z=173-38=135.

Hence,

The number of free throws, z= 135

The number of two-point throw, x=173

The number of three-point throw, y=111.

3 0
3 years ago
Work out the volume of a cuboid 2cm by 4cm by 5cm
andrew-mc [135]
For a cuboid's volume you simply go length x width x heigth so 2x4x5 so it's 40.
3 0
3 years ago
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