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lapo4ka [179]
3 years ago
5

An athletic field currently has a width of 100 yards and a length of 60 yards. The school plans do expand both the length and th

e width of the field by x yards. What polynomial in standard form represents the area of the expanded athletic field?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0
(x+60)(x+100)
x²+160x+6000
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The hypotenuse of a right-angled triangle is 61 cm. If one of the remaining two sides is
igomit [66]

Answer:

60cm

Step-by-step explanation:

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If y=x+2 we’re changed to y=x-1 how would the graph of a new function compare with the first one
butalik [34]

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6 0
3 years ago
Need someones help on this!
Paha777 [63]

Answer:

1st, 3rd, and 4th box.

Step-by-step explanation:

9^5=59049

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9^5=59049   59049x9=531441                     no

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4 0
3 years ago
Read 2 more answers
Please help please help me out
Lapatulllka [165]
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3 0
3 years ago
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Please view picture. Also please tell mehow you got the answer
Cerrena [4.2K]
Have a look at the image attachment. I've added the points A, B, C, D such that
A = base of the diving board pole, or location of the pool deck
B = the location 1.6 meters directly above point A
C = location of the person's eyes
D = diving board location
The goal is to find the length of segment AD

We are given
AB = 1.6
BC = 3.67
what we want to find is
BD = x

Due to the fact we have similar right triangles ABC and CBD, we can form the proportion below and solve for x
AB/BC = BC/BD
1.6/3.67 = 3.67/x
1.6*x = 3.67*3.67
1.6*x = 13.4689
1.6*x/1.6 = 13.4689/1.6
x = 8.4180625

So BD is 8.4180625 meters
Use this to find the length of AD
AD = AB + BD
AD = 1.6 + 8.4180625
AD = 10.0180625
which rounds to 10.0 meters when rounding to the nearest tenth (one decimal place)

------------------------------------------------------------------------------------------

Answer: choice D) 10.0 m

7 0
3 years ago
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