Question

If(x)=x/2-3 and g(x)=4x2+x-4 find (f+g)(x)

Answer 1

$(f+g)(x)=4x^2+\frac{3}{2}x-7$

Answer 2

Answer:

$h(x)=4x^2+\dfrac{3}{2}x-7$

Step-by-step explanation:

Given:  

$f(x)=\dfrac{x}{2}-3$

$g(x)=4x^2+x-4$

To find: (f+g)(x)

It is a composite function. Sum of f and g function.

$h(x)=f(x)+g(x)$

$h(x)=\dfrac{x}{2}-3+4x^2+x-4$

Combine the like term

$h(x)=4x^2+\dfrac{3}{2}x-7$

Hence, The sum of f(x) and g(x) would be $h(x)=4x^2+\dfrac{3}{2}x-7$