Hello,
tan C=AB/BC==>BC=tan 49° * 250=287,59210... (feet)
sin C=AB/AC==>AC=250/sin 49°=331,253248... (feet)
tan C=AB/BC==>BC=tan 49° * 250=287,59210... (feet)
sin C=AB/AC==>AC=250/sin 49°=331,253248... (feet)
Which pair of non-congruent figures must be similar? two squares two parallelograms (not rectangles) two right triangles two iso
sceles triangles (not equilateral)
1 answer:
You might be interested in
The ratios StartFraction U V Over Z Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over X Y EndFraction are equivalent.
<h3>Similarity theorem of triangles</h3>For two triangles to be similar, the ratio of the measure of similar sides of the triangle must be equal to a constant known as a scale factor.
From the given figures, the expression that can be used to prove that the triangles are similar is as shown;
UV/ZY = WU/ZX = WV/XY
Hence the correct option is to show that the ratios StartFraction U V Over Z Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over X Y EndFraction are equivalent.
Learn more on similar triangles here; brainly.com/question/11920446
#SPJ1
