Answer:
1.2 kg
Step-by-step explanation:
We need 400 grams of potatoes for 4 people. That means each person will require 400 / 4 = 100 grams.
Now, we have 12 people, so the total number of grams needed will be:
(100 g/person) * (12 people) = 1200 grams
However, we want the answer in kilograms. There are 1000 grams in a kilogram, so divide 1200 by 1000:
1200 / 1000 = 1.2 kg
The answer is 1.2 kg.
The missing side is 17 and rounded it is 20
Answer:
a) Scores of 2 and higher are significantly high
b) Scores of -2 and lower are significantly low
c) Scores between -2 and 2 are not significant.
Step-by-step explanation:
Mean = 0
Standard deviation = 1
a. significantly high (or at least 2 standard deviations above the mean).
2 standard deviations above the mean is:
0 + 1*2 = 2
So scores of 2 and higher are significantly high
b. significantly low (or at least 2 standard deviations below the mean).
2 standard deviations below the mean is:
0 - 1*2 = -2
So scores of -2 and lower are significantly low
c. not significant (or less than 2 standard deviations away from the mean).
2 standard deviations above the mean is:
0 + 1*2 = 2
2 standard deviations below the mean is:
0 - 1*2 = -2
So scores between -2 and 2 are not significant.
Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
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Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
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Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
You add 9 to both sides to get:
<span>y – 9 + 9 = –17 + 9
</span>
so it's <span>Addition Property of Equality
answer
</span>B.Addition Property of Equality
