Answer:
7.49% of Mercury
Explanation:
Let N₀ represent the original amount.
Let N represent the amount after 10 days.
From the question given above, the following data were obtained:
Rate of disintegration (K) = 0.0108 h¯¹
Time (t) = 10 days
Percentage of Mercury remaining =?
Next, we shall convert 10 days to hours. This can be obtained as follow:
1 day = 24 h
Therefore,
10 days = 10 day × 24 h / 1 day
10 days = 240 h
Thus, 10 days is equivalent to 240 h.
Finally, we shall determine the percentage of Mercury remaining as follow:
Rate of disintegration (K) = 0.0108 h¯¹
Time (t) = 10 days
Percentage of Mercury remaining =?
Log (N₀/N) = kt /2.303
Log (N₀/N) = 0.0108 × 240 /2.303
Log (N₀/N) = 2.592 / 2.303
Log (N₀/N) = 1.1255
Take the anti log of 1.1255
N₀/N = anti log 1.1255
N₀/N = 13.3506
Invert the above expression
N/N₀ = 1/13.3506
N/N₀ = 0.0749
Multiply by 100 to express in percent.
N/N₀ = 0.0749 × 100
N/N₀ = 7.49%
Thus, 7.49% of Mercury will be remaining after 10 days
