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1 year ago

What is pure substancesubscribe this channel

Chemistry

1 answer:

irina [24]1 year ago

8 0

A pure substance is a material made of only one type of particle.

What is pure substance?

A substance that has fixed in chemical composition throughout is called a pure substance such as water, air and nitrogen. The pure substance doesn't have to be of a single element or compound. A pure substance consists only of one element for the or one compound. a mixture consists of two or more different substances, not chemically joined together.

Examples of pure substance include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and the baking soda (sodium bicarbonate). Crystals, in general, are pure substances.

Elements are the pure substances that cannot be broken down into simpler substances by any physical or chemical means we know as they have only one kind of atom at the entire composition. Thus when gold is tjr broken down it still remains gold and hence is considered a pure substance is and an element.

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3 years ago

Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made

arlik [135]

Answer: The empirical formula is $C_3H_3O$ .

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 12.24 g

Mass of $H_2O$ = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, = $\frac{12}{44}\times 12.24=3.338g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, = $\frac{2}{18}\times 2.505=0.278g$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.278}{0.104}=3$

For H = $\frac{0.278}{0.104}=3$

For O = $\frac{0.104}{0.104}=1$

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is $C_3H_3O$ .

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3 years ago

Chlorine is the most widely used disinfectant for killing pathogens during water treatment. Determine the kilograms of chlorine

makkiz [27]

Explanation:

The given data is as follows.

Flow of chlorine (Q) = $10,000 m^{3}/day$

Amount of liter present per day is as follows.

$10,000 \times 10^{3} l/day$

It is given that dosage of chlorine will be as follows.

10 mg/l = $10 \times 10^{-6}$ kg/l

Therefore, total chlorine requirement is as follows.

Total chlorine requirement = $(10,000 \times 10^{3}) \times (10 \times 10^{-6})$ kg/day

= 100 kg/day

Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.

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3 years ago

Why must the mass of magnesium be less than 0.09 g?

SVEN [57.7K]

The mass of magnesium should be less than 0.09g to enable a faster reaction rate. Magnesium reacts to form a white coating around it which stops the reaction. The lesser the gram the faster the reaction before the coating is formed. It is also advisable to use magnesium fillings to increase the rate of reaction.

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3 years ago

What is pure substancesubscribe this channel​

What is pure substancesubscribe this channel