It’s 34. hope this helps xx
Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer:
make a table of values
Step-by-step explanation:
then plot using those values
Answer:
12 x^4 + 18 x^3 - 9 x^2 thus D is the correct answer.
Step-by-step explanation:
Expand the following:
3 x^2 (4 x^2 + 6 x - 3)
3 x^2 (4 x^2 + 6 x - 3) = 3 x^2 (4 x^2) + 3 x^2 (6 x) + 3 x^2 (-3):
3 4 x^2 x^2 + 3 6 x^2 x - 3 3 x^2
3 (-3) = -9:
3 4 x^2 x^2 + 3 6 x^2 x + -9 x^2
3 x^2×6 x = 3 x^(2 + 1)×6:
3 4 x^2 x^2 + 3×6 x^(2 + 1) - 9 x^2
2 + 1 = 3:
3 4 x^2 x^2 + 3 6 x^3 - 9 x^2
3×6 = 18:
3 4 x^2 x^2 + 18 x^3 - 9 x^2
3 x^2×4 x^2 = 3 x^4×4:
3×4 x^4 + 18 x^3 - 9 x^2
3×4 = 12:
Answer: 12 x^4 + 18 x^3 - 9 x^2
Answer:
7
Step-by-step explanation:
12-(-3)-2(4)
12-(-3)-8
15-8=7
