Question

What is the value of sec theta given the diagram below?

Answer 1

Answer:

$\sec \theta=-\sqrt{5}$

Step-by-step explanation:

The hypotenuse is $h^2=6^2+3^2$

$h^2=36+9$

$h^2=45$

$h=\sqrt{45}$

$h=3\sqrt{5}$

The terminal side of $\theta$ is in the second quadrant.

In this quadrant; the secant ratio is negative.

$\sec \theta=-\frac{hypotenuse}{adjacent}$

$\sec \theta=-\frac{3\sqrt{5}}{3}$

$\sec \theta=-\sqrt{5}$

Answer 2

Answer:

a on ed

Step-by-step explanation: