3 years ago

Which of these expressions is equivalent to 6x - 10x + 20?

Mathematics

1 answer:

zhenek [66]3 years ago

5 0

Answer:

The answer is=B

Good luck

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From the top of a building, 40 feet above the ground, a construction worker locates a rock at a 12° angle of depression. How far

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188 m

Step-by-step explanation:

$\tan(12) = \frac{40}{x} \\ x = \frac{40}{ \tan(12) } \\ x = 188$

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Step-by-step explanation:

the column (x) the numbers go up by 4 every time and the (y) column goes up by 7 every time

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Down 6
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3 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

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3 years ago

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The difference was 62 degrees.
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