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4 years ago

6

Round 657 to the nearest ten

2 answers:

STALIN [3.7K]4 years ago

4 0

660 would be the nearest ten. you round up because the final number is with 5 or greater. if the final number was 4 or less, you would round down. I hope this helped you

Hatshy [7]4 years ago

4 0

660 would be the nearest ten. Sorry if it's to late to answer.

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3 years ago

How do you solve this type of problem, what would be the procedure? Assume PQRS is a parallelogram, if PQ=x2−10 and SR=3x , find

NeTakaya

Answer:

<em /> $x = 5$ <em />

<em />

Step-by-step explanation:

Given

Shape: Parallelogram PQRS

$PQ = x^2 - 10$

$SR = 3x$

Required

Find all possible values of x

<em>Every parallelogram have parallel and equal opposite sides;</em>

From the given parameters, one can easily deduce that PQ and SR are opposite sides;

This implies that

$PQ = SR$

Substitute values of PQ and SR

$x^2 - 10 = 3x$

Subtract 3x from both sides

$x^2 - 10 -3x = 3x - 3x$

$x^2 - 10 -3x = 0$

Rearrange

$x^2 -3x- 10 = 0$

Now, we have a quadratic equation;

Expand the above expression

$x^2 +2x-5x- 10 = 0$

Factorize

$x(x+2)-5(x+2) = 0$

$(x-5)(x+2) = 0$

$x - 5 = 0$ or $x + 2 = 0$

Solve for x in both cases

<em /> $x = 5$ <em> or </em> $x = -2$ <em />

<em />

<em>But x can't be negative;</em>

<em>So, the possible value of x is </em>

<em /> $x = 5$ <em />

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3 years ago

Solve for g.<br> 4(g - 17) = 12<br> g=

VARVARA [1.3K]

Answer:

$g=20$

Step-by-step explanation:

$4\left(g-17\right)=12$

Divide both sides by 4:

$\frac{4\left(g-17\right)}{4}=\frac{12}{4}$

$g-17=3$

Add 17 to both sides:

$g-17+17=3+17$

$g=20$

4 0

3 years ago

Read 2 more answers