Answer:
(a) The exact value that is 33% of 2302 is 759.66.
(b) No, the result from part (a) could not be the actual number of adults who said that they play basketball.
(c) The actual number of adults who said that they play basketball is 760.
(d) 11.82% of respondents said that they only play hockey.
Step-by-step explanation:
We are given that a polling company reported that 33% of 2302 surveyed adults said that they play basketball.
(a) The exact value that is 33% of 2302 is given by;
=
= 759.66
(b) No, the result from part (a) could not be the actual number of adults who said that they play basketball because the value in part (a) is in fractions or in decimals and the number of people can't be in fractions. It must be a whole number.
(c) The actual number of adults who said that they play basketball is 760. {As 759.66 rounded to one decimal point}
(d) It is given that among the 2302 respondents, 272 said that they only play hockey.
Percentage of respondents who said that they only play hockey is given by;
=
= 11.82% ≈ 12%
So, first lets define our variables:
let x = the number of dimes
let y = the number of nickels
so our first equation would be x+y = 16
Since dimes are 10 cents and nickels are 5 cents the next equation would be as follows:
.10x+.05y = 1.35
now change the first equation so y = -x+16
now substitute:
.10x+.05(-x+16) = 1.35
then multiply so you get .10x+-.05x+0.8=1.35
combine like terms and you get .05x+0.8 = 1.35
then subtract 0.8 from both sides and you get .05x = 0.55 then subtract
and you get x = 11 then substitute 11 for where x should be and you should get y = 5
So, you have 11 dimes and 5 nickels
The answer for this is 42. just subtract 152 from 68 and then divide that by 2.
Soccer ball reaches its highest position when its equation turns from positive slope to zero and then negative. Mathematically it is where the derivative of the its function equals to zero. so:
d(-3x^2 + 6x + 3) / dx = -6x + 6
-6x + 6 = 0 -> x = 1 ->
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it seems Paige's ball reaches higher than Viaola's with only 6 meters height.
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².
To find the perimeter of each, we add the area of all sides. For the first figure, the missing sides are 1 cm and 6 cm. To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.
For the second figure, the missing sides are 4 cm and 3 cm. To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.
For the third figure, the missing sides are 3 cm, 3 cm and 8 cm. To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.
For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm. To find the area, we have two squares whose dimensions are 10x10.
For the fifth figure, the missing sides are 3 cm and 9 cm. To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.