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3 years ago

A merchant bought 30 dozen pairs of gloves. How many individual gloves did the merchant buy?

Mathematics

2 answers:

dangina [55]3 years ago

8 0

Answer:

720 is the correct answer

Step-by-step explanation:

gtnhenbr [62]3 years ago

3 0

In this question there are several information's of immense importance already given.
The number of pair of gloves that the merchant bought = 30 dozens
1 dozen = 12 gloves
Also
1 pair = 2 gloves
Then
The total numberof individual gloves bought
by the merchant = 30 * 12 * 2
= 720
The correct option among all the options given in the question is option "C" and it can be checked via the above solution.

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A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of

Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

Hours of TV per week (X): 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of hours of TV watched per week = $\frac{\sum X}{n}$ = 9.65

s = sample standard deviation = $\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }$ = 4.61

n = sample of people = 20

$\mu$ = true average number of hours of TV watched per week

Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 80% confidence interval for the true average, $\mu$ is ;

P(-1.33 < $t_1_9$ < 1.33) = 0.80 {As the critical value of t at 19 degrees of

freedom are -1.33 & 1.33 with P = 10%}

P(-1.33 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.33) = 0.80

P( $-1.33 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $9.65-1.33 \times {\frac{4.61}{\sqrt{20} } }$ , $9.65+1.33 \times {\frac{4.61}{\sqrt{20} } }$ ]

= [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0

3 years ago

Which equation does not represent a function?

Vinvika [58]

Answer:

A function is a line where every x has only one solution y.

The answer is D because x has more than one solution.

Step-by-step explanation:

3 0

3 years ago

Joianie beleives that you cannot use cross products to solve the proportion 50/3 = 75/x for x. She says

BigorU [14]

Answer:

4.5 It doesn't come out evenly, but cross products do work.

Step-by-step explanation:

She is not correct.

50 * x = 3 * 75 Combine the right

50x = 225 Divide by 50

x = 225/50

x = 4.5

6 0

3 years ago

WILL GIVE BRAINLYEST

Svetach [21]

Answer:

well it uses the compound interest formula

F(x) = P_{0}(1 + \frac{r}{100})^x

so in your question

x = time in years for the initial formula

P_{0} = 293,.... r = 6% ...and...

then you need to substitute x = 4

simplify the brackets and you should get the answer.

6 0

3 years ago

Read 2 more answers

A(n)___ in the money supply will cause interest rates to decrease, which, in turn, causes spending to____.

puteri [66]

I think the answer would be A because if the money rates go up more people don’t want the expenses

4 0

3 years ago