As we know that angle of semi circle is 180°.
Here,
FLG = 40°
GLH = ?
HLJ = 60°
FLG + GLH + HLG = 180°
40° + GLH + 60° = 180°
GLH + 100° = 180°
GLH = 180° - 100°
GLH = 80°
Now,
FLH = 40° + 80° = 120°
Answer:
about 50
Step-by-step explanation:
that's all I can think of
Answer: y=1.5
Step-by-step explanation: Isolate the variable by dividing each side by factors that don’t contain the variable.
Answer:x=31.4919
Step-by-step explanation:
Step1:isolate a square root on the left hand side√x+3=√2x-1-2
Step2:eliminate the radicals on the left hand side
Raise both sides to the second power
√x+3)^2=(√2x-1-2)^2
After squaring
x+3=2x-1+4-4-4√2x-1
Step3:get the remaining radicals by itself
x+3=2x-1+4-4√2x-1
Isolate radical on the left hand side
4√2x-1=-x-3+2x-1+4
4√2x-1=x
Step4:eliminate the radicals on the left hand side
Raise both side to the second power
(4√2x-1)^2=x^2
After squaring
32x-16=x^2
Step 5:solve the quadratic equation
x^2-32x-16
This equation has two real roots
x1=32+√960/2=31.4919
x2=32-√960/2=0.5081
Step6:check that the first solution is correct
Put in 31.4919 for x
√31.4919+3=√2•31.4919-1-2
√34.492=5.873
x=31.4919
Step7:check that the second solution is correct
√x+3=√2x-1-2
Put in 0.5081 for x
√0.5081+3=√2•0.5081-1-2
√3.508=-1.873
1.873#-1.873
One solution was found
x=31.4919
Answer:
m=1/300 du
Step-by-step explanation:
we have that m=∫∫rho(x,y)dA for this we must find the limits of integration (according to the graph1)
On the x axis: if y=2x and x+2y=1 then y=2x and y=(1-x)/2 ⇒ 2x=(1-x)/2 ⇒ 4x=1-x ⇒ 5x=1 ⇒ x=1/5; on the y axis y=0 and y=1/2
m=∫∫rho(x,y)dA (view the graph 2)
