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Ludmilka [50]
2 years ago
11

Please please help please please help me help me

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
8 0

Answer:

\frac{3}{4}

Step-by-step explanation:

You have to find the difference between two variables that are continuously listed for example: -9,-5. If the list is going up, you'll sum them, if it's going down, you subtract them.

\frac{7-4}{(-9)-(-5)}\\=\frac{3}{4}

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a box contains 5 plain pencils and 5 pens. a second box contains 7 color pencils and 5 crayons. one item from each box is chosen
Ket [755]
First box: \dfrac{pen}{total}=\dfrac{5}{10}=\dfrac{1}{2}

Second box: \dfrac{crayon}{total}=\dfrac{5}{12}

Multiply them:

\dfrac{1}{2}*\dfrac{5}{12}=\dfrac{5}{24}

The probabilityis \dfrac{5}{24}
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3 years ago
PLLLLSSS HELP ME ASAP!
erastovalidia [21]
The answer to the first one is ' D '.
(All the angles inside a triangle have to add up to exactly 180 degrees.)

The answer to the second one is  ' C ' .
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3 0
3 years ago
Situation D: Suppose that, in a one-minute period during an electrical storm, the number of lightning strikes on a radar antenna
Crank

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In this question:

\mu = 2.40

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177

21.77% probability that the antenna will be struck exactly once during this time period.

3 0
3 years ago
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