We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
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(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
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(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
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(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
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(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
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(1) z = 113 - 1100*y
(2) 400*y = 40
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(1) z = 113 - 1100*y
(2) y = 40/400
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(1) z = 113 - 1100*y
(2) y = 1/10
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if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.
Consider the ordering
... -2 < -1
Now consider the ordering of their absolute values:
... 1 < 2
_____
Hopefully, you see that changing the sign reflects the sequence across the origin, so that the ordering is reversed when the signs are changed.
Answer:
The width of rectangle is 1 unit.
Step-by-step explanation:
Given:
The area of rectangle is 6 units and its width is 5 units less than the length.
So, to find the width of rectangle.
Let the length be
and the width be
.
Now, to find the width we put the formula of area of rectangle:
Area = length × width






<em>On solving equation we get:</em>

Therefore, we take the value x=6 as it is positive value:


So, the width of rectangle:
Width = 
= 
= 
Therefore, the width of rectangle is 1 unit.
simplify exponent: 20*(9-4)/50
simplify parentheses: 20*5/50
multiply: 100/50
divide: 2