Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Since a whole rotation is 360 degrees, you can take the whole rotation subtract it by the minor arc (92 degrees) which will equal the major arc (B=268 degrees)
7x+(x-4)(X+5)-5x
7x+(X*2+ 5x-4x-20)-5x
7x+(X*2+ x-20)-5x
X*2+3x-20
Option E:
The value of m that makes the inequality true is 5.
Solution:
Given inequality is 3m + 10 < 30.
Let us first simplify the expression.
3m + 10 < 30
Subtract 10 from both side of the equation.
3m < 20 – – – – (1)
<u>To find the value of m that makes the inequality true:</u>
Option A: 20
Substitute m = 20 in (1),
⇒ 3(20) < 20
⇒ 60 < 20
It is not true because 60 is greater than 20.
Option B: 30
Substitute m = 30 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option C: 8
Substitute m = 8 in (1),
⇒ 3(8) < 20
⇒ 24 < 20
It is not true because 24 is greater than 20.
Option D: 10
Substitute m = 10 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option E: 5
Substitute m = 5 in (1),
⇒ 3(5) < 20
⇒ 15 < 20
It is true because 15 is less than 20.
Hence the value of m that makes the inequality true is 5.
Option E is the correct answer.
