Answer:
Fourth option: 30 days
Step-by-step explanation:
We three path to complete the project:
Path A:
A1 → A2 → A3
10 days → 8 days → 9 days = 27 days
Path B:
B1 → B2 → B3
2 days → 7 days → 3 days = 12 days
Path C:
C1 → C2 → C3
10 days → 8 days → 12 days = 30 days
Then the duration of the critical path is 30 days, we can't conclude the project until each path has finished
Answer: g(x) has the smallest possible y-value of -3
<u>Step-by-step explanation:</u>
f(x) = 3ˣ - 3 <em>This is an exponential graph shifted down three units. So, it has an asymptote at y = -3, which means it approaches -3 but does not touch it.</em>
Range: y > 3 (-3, ∞)
g(x) = 7x² - 3
⇒ g(x) = 7(x - 0)² - 3 <em>This is a parabola with vertex at (0, -3) </em>
Range: y ≥ 3 [-3, ∞)
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m
Answer:
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The answer is b) :) hope i helped!
