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weqwewe [10]
2 years ago
12

ILL MARK BRAINLIEST

Mathematics
2 answers:
Snezhnost [94]2 years ago
8 0

Answer:

The answer is 3

Alex73 [517]2 years ago
8 0

Answer:

3

Step-by-step explain

there are 3 groups of 10 that makes 30 so the answer is 3

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The quotient of w and 5 is at least 25
const2013 [10]
I think the answer is 5 because 25 divided by 5=5

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3 years ago
Read 2 more answers
Name the shortest segment from Point A to Line CD. Write and Solve an inequality for X.
Misha Larkins [42]
Attached the solution with work shown.

5 0
3 years ago
What is the supplementary angle to an angle that has 112 degrees?
olga55 [171]
Supplementary means they add up to 180°.
180-112= 68
The answer is 68°
7 0
3 years ago
Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?
9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

f(x)=\frac{(x-1)(x^2-4)}{x^2-a}

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that x=\sqrt{a} will annulate the denominator, i.e

(\sqrt{a})^2-a = a-a = 0. But, if a = 1 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}

so, the value x=\sqrt{a} = \sqrt{1} = 1 won't annulate the denominator.

Now, for a = 4 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1

so, the value x=\sqrt{a} = \sqrt{4} = 2 won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0
3 years ago
Solve the equation for y. Identify the slope and y-intercept then graph the equation.
viva [34]

Answer:

y = -3    m = -1     b = 3

Step-by-step explanation:

-3y=3x-9

To isolate the y variable, divide both sides by -3.

y = -1x + 3

y = -3

m = -1

b = 3

8 0
3 years ago
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