<h2>Steps:</h2>
So firstly, since we know that the coefficient of x² is 1, this means that this is our base equation:
y = x² + bx + c
Now, since we know that the roots are -7 and 1, set y = 0 and set x = -7 and 1 and simplify:
Now with this, we can set up a system of equations to solve for b and c. For this, I will be using the elimination method. For this, subtract the 2 equations:
Now that the c variable has been eliminated we can solve for b. For this, divide both sides by -8 and your first part of your answer is b = 6.
Now that we know the value of b, plug it into either equation to solve for c:
<h2>Answer:</h2>
<u>Putting it together, your final answer is x² + 6x - 7 = 0.</u>
Answer/Step-by-step explanation:
Part A:
![Key:\left[1 Adult = 4 Student]](https://tex.z-dn.net/?f=Key%3A%5Cleft%5B1%20Adult%20%3D%204%20Student%5D)
<u> 12 Student = 3 Adult</u>
<u>24 Student = 6 Adult</u>
<u>40 Student = 10 Adult</u>
Part B:
33 Student
Hence, divide 33 by 4 = 8 with a remainder of 1.
Therefore, 8 Adult and for the remainder 1 student either one Adult takes 5 Student or Needed 9 Adult.
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
If the factored form is given by
Then its standard form will be given by
if factored form is given by
Then its standard form will be given by
Hence, only first option is correct.
If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
