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Dovator [93]
2 years ago
5

What is the perimeter of the rectangle?

Mathematics
1 answer:
lara [203]2 years ago
4 0

Answer:

A 6x+11 that is the answer

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Please help. Thank you
Inessa [10]

Given:

PQRS\sim TUVW

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

PQRS\sim TUVW

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

k=\dfrac{VW}{RS}

k=\dfrac{25}{35}

k=\dfrac{5}{7}

Therefore, the scale factor from PQRS to TUVW is k=\dfrac{5}{7}.

6 0
3 years ago
Solve this query plzzz​
Olin [163]

Step-by-step explanation:

\frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   = \tan \:A \\  \\ LHS =  \frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   \\  \\  =  \frac{2\sin \:2A.\cos \:2A}{\cos \:2A}   \times  \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\  \\  = 2\sin \:2A   \times  \frac{1 - 2 { \cos}^{2}A  +  1}{1 - 2 { \cos}^{2}2A  + 1 } \\  \\  = 2\sin \:2A   \times  \frac{2- 2 { \cos}^{2}A  }{2 - 2 { \cos}^{2}2A   } \\  \\   = 2\sin \:2A   \times  \frac{2(1 - { \cos}^{2}A)  }{2 (1-  { \cos}^{2}2A)   } \\  \\   = 2\sin \:2A   \times  \frac{1 - { \cos}^{2}A}{1-  { \cos}^{2}2A   } \\  \\     = 2\sin \:2A   \times  \frac{ { \sin}^{2}A}{{ \sin}^{2}2A   } \\  \\    = 2  \times  \frac{ { \sin}^{2}A}{{ \sin}2A   } \\  \\   = 2  \times  \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \:   A } \\  \\   = \frac{ { \sin}A}{ \cos \:   A }  \\  \\  = tan \: A \\  \\  = RHS \\

7 0
3 years ago
-19&gt;g-24<img src="https://tex.z-dn.net/?f=%20%20-%2019%20%5C%20%20%5Ctextgreater%20%5C%20%20g%20-%2024" id="TexFormula1" titl
KatRina [158]
\begin{gathered} -19>g-24 \\ -19+24>g \\ 5>g \end{gathered}

start by adding 24 on both sides and simplify

6 0
1 year ago
I NEED HELP WITH thiss
Ainat [17]
X=8 is the Answer.  So the equation would be <span>-8+4(1+5 times 8 )=156 </span>
6 0
3 years ago
-mb-m^2 for m=3.48 and b=96.52
AlekseyPX
I- huh I don’t understand the question
3 0
3 years ago
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