Answer:
The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.
Step-by-step explanation:
In order to solve this problem we first need to attribute variables to the unkown quantities. We will call the average salary of Master's "x" and the average salary of a Bachellor's "y". The first information the problem gives us is:
x = 2*y - 46
The second one is:
x + y = 113
We now have two equations and two variables, so we can solve the system. To do that we will use the value for x from the first equation on the second one. We have:
2*y - 46 + y = 113
3*y = 113 + 46
3*y = 159
y = 159/3 = 53
x = 2*(53) - 46 = 60
The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.
Answer:
20
Step-by-step explanation:
the number next to the variable is the coefficient.
20 is the coefficient, while w is the variable
For this case we have the following function:

To find the zeros of the function we make
and solve for "x", then:

We multiply by -1 on both sides of the equation:

We factor the equation, for this we look for two numbers that, when multiplied, result in 36 and when added, result in -13. These numbers are -9 and -4.

Thus, the factored equation is:

Therefore, the roots are:

Answer:

Answer:
Question 13. I believe is C.
Step-by-step explanation:
take your area of the face you are given aka your 7 5/6 and multiply it by six since there are six faces.
You can convert the mixed number to an improper fraction
= denominator times the whole number ( 6x7)= then add the numerator (42+5)=
Then multiply by six to get your answer
I'm not completely sure about question number fourteen so I am not answering it.
Answer:
See the second attachment for long division by hand. The first attachment shows the "work" I would usually do.
Step-by-step explanation:
In college math, you are generally expected to be able to make use of a scientific and/or graphing calculator. Division is one of the simpler operations these devices can perform.
If you are doing long division by hand, use the method you were taught in 3rd or 4th grade. The one shown is one of several different methods being taught now.