At heart we're being asked for a line through two points,

In general the line through (a,b) and (c,d) is

Check that you understand why both (a,b) and (c,d) are on this line.
Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,





That's our answer; let's check it.
When T=40, v = (5/9)40 + (2995/9) = 355 good
When T=49, v= (5/9)49 + (2995/9) = 360 good
You didn't show all answer choices unfortunately, but basically during neap tide, the moon is either above or below the earth, in pictures (vertical). And the right half will always be in shadow.
~Hope this helps
Answer:
we can use division to solve real life problem such as: how much candy each of 5 students will receive if 20 candy are shared equally
Step-by-step explanation:
cause 20/5 = 4
Its A. Hope this helps, message me for further questions.
0.3(12y)
= 3.6y
hope this helps :)