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Tresset [83]
3 years ago
10

Hi can you match these for me :(

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:1c .          3a .             4b .           5d .       2e    

Step-by-step explanation:sorry if wrong not super good

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Simplify the linear expression.<br> −4x+5(−5x−1)<br> plz help
MA_775_DIABLO [31]

Answer:

-29x-5

Step-by-step explanation:

4 0
2 years ago
Which of the following are independent variables?
Lapatulllka [165]

Answer:

i think that it is oil

Step-by-step explanation:

because it does not change

4 0
3 years ago
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Given log3 2=0.631 log3 7=1.771 what is log3 14?
Leni [432]
In logarithm, inverse operations are applied.
log_3{14} =  log_3{7} +   log_3{14} \\ log_3{14} = 0.631 + 1.771 \\log_3{14} = 2.402
5 0
3 years ago
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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
3 years ago
Ariana bought 5 dozen pears at $36 per dozen . She discovered that 7 were rotten and she sold the rest at $4.50 each . Calculate
GrogVix [38]

Step-by-step explanation:

1 dozen = 12 pears

12 pears = $36

1 pear = 36/12 = $3

Total Cost of Pears = No. of pears x price of 1 pear

= (5x12) x 3

= 60 x 3

= $180

Sale of Pears = Price per pear x (Total Pears bought - Rotten Pears)

= $4.50 x (5x12-7)

= $4.50 x 53

= $238.50

Profit/Loss = Sale of Pears - Total Cost of Pears

= $238.50 - $180

= $58.50

Ariana made a profit of $58.50.

5 0
3 years ago
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