25 1/5 - 17 5/6 <br><br> as a mixed number with the fractional part in lowest terms

The hypotenuse is the side across from the right angle, and it's also the longest side of the triangle.

nalin [4]

Yes You are correct.

5 0

3 years ago

Read 2 more answers

I don’t know how to do this

stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as $x$ approaches the edges. For example,

$g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}$

has two pieces, $2x+5$ and $x^2-10$ , both of which are continuous by themselves on the provided intervals. In order for $g$ to be continuous everywhere, we need to have

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)$

By definition of $g$ , we have $g(-3)=2(-3)+5=-1$ , and the limits are

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1$

$\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1$

The limits match, so $g$ is continuous.

For the others: Each of the individual pieces of $f,h$ are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0

3 years ago

Is 19/72 greater than 1/4

alina1380 [7]

Answer:

Yes

Step-by-step explanation:

$\frac{1}{4} = \frac{1 \times 18}{4 \times 18} = \frac{18}{72} \\ \because \: 19 > 18 \\ \therefore \: \frac{19}{72} > \frac{1}{4} \\$

7 0

3 years ago

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Which graph represents this equation?<br> y = 1/2x^2 + 2x - 6

s2008m [1.1K]

Answer:

C

Step-by-step explanation:

y = 1/2x^2 + 2x - 6

When, x = 0, y = - 6

you don't need to find another variable. Because in number C u can find a graph that has y= -6 when x =0.

6 0

3 years ago

B.

Helen [10]

Answer:

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

Step-by-step explanation:

The given figure consists of three triangles

1. ΔUJN, 2. ΔUGN, and 3. ΔUJG

Whereby segment UN is perpendicular to segment JG, we have;

ΔUJN and ΔUGN are right triangles

∴ ∠UNJ = ∠UNG = 90° by definition of segment UN being perpendicular to segment JG

NU ≅ NU by reflexive property

Whereby UN bisects ∠JUG and segment JG, we have;

JN = GN by definition of a bisected segment

Therefore, we have;

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

7 0

3 years ago

25 1/5 - 17 5/6 as a mixed number with the fractional part in lowest terms