The idea is to group up the terms into two groups, factor each group and then factor out the overall GCF
2x - 18 + xy - 9y
(2x - 18) + (xy - 9y)
2(x - 9) + (xy - 9y)
2(x - 9) + y(x - 9)
(2 + y)(x - 9)
(x - 9)(2 + y)
Answer: Choice B
Answer:
D
Step-by-step explanation:
Firstly, since it is a selection question, we shall be using a combination approach.
So here we are trying to select the best answer that describes that 2 out of 10 students are selected.
Let’s consider the scenario below;
selecting r out of n can be resolved using the combination nCr
= n!/(n-r)!r!
Now in this case, our n = 10 and r = 2.
Thus, 10C2, we have ;
10!/(10-2)!2! = 10!/8!2! = (10 * 9 * 8!)/8!2! = (10 *9)/2! = 90/2 = 45
Thus, 10C2 = 45
Here, the order of selection does not matter as we can select in random fashion. This makes option D correct
Answer:
D) y=0.75x+1
Step-by-step explanation:
Because this is a positive parabola, it opens upwards, like a cup, and the vertex dictates what the minimum value of the function is. In order to determine the vertex, I recommend completing the square. Do that by first setting the function equal to 0 and then moving the 9 to the other side by subtraction. So far:
. Now, to complete the square, take half the linear term, square it, and add that number to both sides. Our linear term is 6. Half of 6 is 3 and 3 squared is 9. So add 9 to both sides.
. The right side reduces to 0, and the left side simplifies to the perfect square binomial we created while completing this process.
. Move the 0 back over and the vertex is clear now. It is (-3, 0). Therefore, 0 is the minimum point on your graph. The first choice above is the one you want.
Answer:
6
Step 1: Solve Square Root
Vx+3=x-3
x+3=(x-3)^2 (squared both sides)
x+3=x^2-6x+9
x+3-(x^2-6x+9)=0
(-x+1)(x-6)=0 (factor left side of equation)
-x+1=0 or x-6=0
x=1 or x=6
When you plug it in to check
1 (Doesn't Work)
6 (Work)
Therefore, 6 is your solution.
