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bogdanovich [222]
4 years ago
5

Help ASAP please(this is filler so that i can post this)

Mathematics
1 answer:
AfilCa [17]4 years ago
5 0

Answer:

I cant see your post...

Step-by-step explanation:


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At the end of her work day, Rosa leaves her office and goes directly to her bank. On the graph that shows the locations of Rosa'
ikadub [295]
Find the distance between the point of bank and the point of office.

\sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}}
\sqrt{(-4 - (-6)^2 + (4 - (-3)^2}
\sqrt{(2)^2 + (7)^2}
\sqrt{4 + 49}
\sqrt{53}


The distance she travels is approximately 7.3 km.

Hope this helps :)
7 0
3 years ago
Marty says he would rather -$5 than $0 do you agree with marty
borishaifa [10]

Answer:

I dont Agree because Your Just Losing 5 dollars Rather Than Losing nothing

Step-by-step explanation:

8 0
3 years ago
Which equation can be used to determine the value of x?
lorasvet [3.4K]

Answer:

(3x + 18) + 93 = 180

23 + X

Step-by-step explanation:

(3x + 18) + 93 = 180, its supplymentery

180 - 93 = 87

87 - 18 = 69

3x = 69

69/3 = 23

23 = X

7 0
2 years ago
Read 2 more answers
Name the postulate or theorem you can use to prove the triangles congruent.
Maru [420]

Answer:

You can use the ASA Postulate to prove the Angle-Angle-Side Congruence Theorem. A flow proof is shown below. If two angles and a nonincluded side of one triangle are congruent to two angles and the corresponding nonincluded side of another triangle, then the triangles are congruent.

Step-by-step explanation:

Hope it helps! Correct me if I am wrong!

I'm sure about my answer!

If you dont mind can you please mark me as brainlest?

Its ok if you don't want to!

3 0
3 years ago
Find the equation of a circle in standard form that is tangent to the line x = -3 at (-3, 5) and also tangent to the line x = 9.
Sedaia [141]

Answer:

  (x -3)² +(y -5)² = 36

Step-by-step explanation:

The center is on the vertical line halfway between the given vertical lines, so is at x=3. It is also on the horizontal line through the point (-3, 5), so is at y=5. The center is 9-3=6 from either tangent line, so this is the radius.

For center (h, k) and radius r, the circle's equation is ...

  (x -h)² +(y -k)² = r²

For (h, k) = (3, 5) and r=6, the equation is ...

  (x -3)² +(y -5)² = 36 . . . . . . . . does not match any choice written here

6 0
4 years ago
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