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bogdanovich [222]
3 years ago
5

Help ASAP please(this is filler so that i can post this)

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

I cant see your post...

Step-by-step explanation:


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In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
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Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

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Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

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Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

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Step-by-step explanation:

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Step-by-step explanation:

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I really need on these cause I really don't know this and I need to understand. please help me please.​
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Answer:

-6m^4-m^3

Step-by-step explanation:

First you move the parenthesis then you group the like terms after you group the like terms you get m^4-7m^4-m^3 which is adding the similar elements and after you add similar elements you get  -6m^4-m^3. Srry if this makes no sense

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