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enot [183]
3 years ago
9

The bells at kings school ring every 6 mins At queens every 5 mins At princess every 9 mins 3 bells ring together at 8:30 When i

s the next time they will ring
Mathematics
2 answers:
zloy xaker [14]3 years ago
4 0
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Find the Lowest Common Multiple:

In this case, it is 90

Add 90 minutes to 8:30

The next time they will ring together is 10:00

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

joja [24]3 years ago
4 0
The next time they will ring together is 10:00
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15 × u= 135<br> ---------------
NARA [144]

Answer:

15u = 135

Divide both sides by 15

u = 135/15 = 9

U is equal to 9

Hope this helps!

8 0
2 years ago
Read 2 more answers
Find the inequalitie for d thank youuu <br><br><br> -7d+8&gt;29
shutvik [7]

Answer:

d<3

Step-by-step explanation:

-7d+8>29

First lets remove the inequality  for know

-7d+8=29

then remember to re add the inequality to the equation

-7d>21

since you divide by negative you switch

d<3

that is your answer

3 0
3 years ago
G(x)=3x^2-5x-9 find g(x+2)
Anna35 [415]
Answer: 3x^2 + 7x -15
I dunno if u want me to factor it tho
7 0
3 years ago
Can someone help with this question? Thank u! :)
MatroZZZ [7]

Answer:

2.50

Step-by-step explanation:

the pattern shown in the miles driven goes up each time by 5000, stating it's going up by a constant of 5000. the cost goes up each time by 2000.

divide 5000/2000 which would give you 2.5

round it by two decimal places which gives you 2.50

7 0
3 years ago
Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x&lt;6
Oksi-84 [34.3K]

Answer:

-1/3

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

9x^2-15x

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

9x^2-15x=6

Subtract 6 from both sides:

9x^2-15x-6=0

Divide everything by 3:

3x^2-5x-2=0

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0

Find the x using the Zero Product Property:

3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

x=-1/3

Assume that the correct symbol is >. Thus,

x>-1/3

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

9x^2-15x

0 is indeed less than six, so our first correct solution is:

x>-1/3

For the second one, do the same thing. We have:

x=2

Assume that the correct symbol is <. Thus:

x

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

9x^2-15x

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

x>-1/3 \text{ and } x

Together, we can write them as:

-1/3

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

6 0
3 years ago
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