In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=29°, and SQ = 5 feet. Find the length of QR to the nearest tenth of a foot.
2 answers:
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Answer:
x = 8
Step-by-step explanation:
Δ TSU and Δ TRV are similar , thus the ratios of corresponding sides are equal, that is
=
, substitute values
=
=
( cross- multiply )
3x = x + 16 ( subtract x from both sides )
2x = 16 ( divide both sides by 2 )
x = 8