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miv72 [106K]
3 years ago
5

7 Tuesday Find the Greatest Common Factor of 16 and 28:

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

The answer is 4.

Step-by-step explanation:

1. find the factors of 16(1,2,4,4,8,16) and of 28(1,2,4,7,14,28)

2. find the highest factor of the two Factored #.(4)

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Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit
Mamont248 [21]
Here, x - y = 2342
x = 2342 + y

Substitute this value into first equation, 
2342 + y + y = 3500
2y = 3500 - 2342
y = 1158/2
y = 579

So, x = 2342 + 579 = 2921

In short, Your Answer would be 2921 contemporary titles

Hope this helps!
3 0
3 years ago
Read 2 more answers
Which equation represents the circle described?
faust18 [17]
ANSWER

{(x - 4)}^{2} +  {(y - 3)}^{2}  =   {2}^{2}

EXPLANATION

The equation of the circle with radius r and centre (a,b) is given by


(x - a)^{2}  +  {(x - b)}^{2}  =  {r}^{2}

The radius is

r = 2

We need to determine the center of the circle from the given equation of another circle, which is,


{x}^{2}  +  {y}^{2}  - 8x - 6y + 24 = 0


We complete the square to obtain,


{x}^{2}  - 8x+  {y}^{2}  - 6y + 24 = 0

{x}^{2}  - 8x+  {y}^{2}  - 6y  =  - 24
{x}^{2}  - 8x+  {( - 4)}^{2} +   {y}^{2}  - 6y  +  {( - 3)}^{2}  =  - 24 +  {( - 3)}^{2} +  {( - 4)}^{2}


{(x - 4)}^{2} +  {(y - 3)}^{2}  =  - 24 +  9+  16




{(x - 4)}^{2} +  {(y - 3)}^{2}  =  1


The centre of this circle is (4,3)


Hence the center of the circle whose equation we want to find is also (4,3).


With this center and radius 2, the required equation is,


{(x - 4)}^{2} +  {(y - 3)}^{2}  =   {2}^{2}


Therefore the correct answer is C.

3 0
3 years ago
Read 2 more answers
(8.75-2.16)÷7.1+(4.5+1.3)÷4.3
kirill [66]

Answer:

2.27700622339

Step-by-step explanation:

Calculated your welcome

7 0
3 years ago
Read 2 more answers
What is 3.4 in fraction
Anna [14]
\rm 3,4= \frac{34}{10}\\\\We\ can\ simplify\ this\ fraction:\\\\\  \frac{34\div2}{10\div2}=\boxed{ \frac{17}{5} }

So,\ \boxed{3.4=\boxed{\frac{17}{5} }}
8 0
3 years ago
Write an equation in slope-intercept form for the following line:<br><br> (-14,1) and (13,-2)
alex41 [277]

Answer:

\large \boxed{y =  -  \frac{1}{9} x -  \frac{5}{9} }

Step-by-step explanation:

In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term is defined as slope in y = mx+b form which is slope-intercept form.

Now we substitute these ordered pairs (x, y) in the formula.

\large{m =  \frac{1 - ( - 2)}{ -14 - 13} } \\  \large{m =  \frac{1 + 2}{ - 27} } \\  \large{m =  \frac{3}{ - 27}  =  -  \frac{1}{9} }

After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is

\large \boxed{y = mx + b}

We already know m-value as we substitute it.

\large{y =  -  \frac{1}{9} x  + b}

We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)

We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.

\large{y = -  \frac{1}{9} x + b} \\  \large{ - 2 =  -  \frac{1}{9} (13) + b} \\  \large{ - 2 =  -  \frac{13}{9}  + b} \\  \large{ - 2 +  \frac{13}{9}  = b} \\  \large{ -  \frac{5}{9}  = b}

Finally, we know b-value. Then we substitute it in our equation.

\large{y =  -  \frac{1}{9} x + b} \\  \large{y =  -  \frac{1}{9} x -  \frac{5}{9} }

4 0
3 years ago
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