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artcher [175]
3 years ago
11

Which is the value of this expression when a = 5 and k = negative 2? (3^2 a^-3)(3 a^-4)^-2

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

5^5=3125

Step-by-step explanation:

Given\ (3^2a^{-3})(3a^{-4})^{-2}\\\\=3^2a^{-3}\cdot(3)^{-2}(a^{-4})^{-2}\\\\=3^2\times3^{-2}\times a^{-3}\times a^8\ \ \ \ \ \ (x^{-m})^{-n}=x^{mn}\\\\=3^{2-2}\times a^{-3+8}\ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \   \ \ x^m\times x^n=x^{m+n}\\\\=3^0\times a^5\ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \  \ \ \  \ \ \ \ x^0=1\\\\=1\times a^5\\\\=a^5\\\\put\  value\  a=5\\\\=5^5\\\\=3125

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