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vodomira [7]
3 years ago
7

If f is a function and f(4). = -8, give the coordinates of the point on the graph of f.

Mathematics
1 answer:
Ann [662]3 years ago
3 0

Answer:b

Step-by-step explanation:

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4x + 5y = 3<br>kx + 15y = 9 find k<br>​
9966 [12]

Answer:

12

Step-by-step explanation:

4x + 5y = 3 ................ (i)

kx + 15y = 9................(ii)

Dividing eqn (ii) by 3, we get,

k/3 x + 5y = 3.............(iii)

Subtracting eqn (iii) by eqn (i), we get,

-4x - k/3 x = 0

or, -(4 - k/3 )x = 0

or, 4 - k/3 = 0/x

or, 4 - k/3 = 0

or, 4 = k/3

or, k = 4*3

:. k = 12 (Ans)

6 0
2 years ago
For what values of x is the expression below defined?
AleksandrR [38]

The answer is x>0 on apex for x value

4 0
2 years ago
A square prism and a cylinder have the same height. The area of the cross-section of the square prism is 314 square units, and t
Crank

Answer:

The volume of the square prism is  6.28 times the volume of the cylinder  

Step-by-step explanation:

Volume of the square prism = cross-section * height

Volume of the cylinder = cross-section * height

Dividing one volume by the other, and replacing with data:

Volume of the square prism / Volume of the cylinder = 314/50 = 6.28

4 0
2 years ago
सैम ने पहले हफ्ते में 27 किग्रा आटा खरीदा और दूसरे हफ्ते
Bogdan [553]

Answer:

सैम ने 9 पाउंड आटा बनाया

Step-by-step explanation:

7 0
3 years ago
Find two consecutive integers whose product is 6 less than the square of the smaller number
Artyom0805 [142]

Answer:

Hi there!

Your answer is:

The smaller integer is -6

The larger integer is -5

Step-by-step explanation:

Two consecutive integers:

x, x+1

Product= multiply

(x) × (x+1) = x^2 - 6

x^2 + x= x^2 -6

-x^2

x= -6

Plug back in

First integer (smaller):

-6

Second integer (larger):

-6+1

-5

<u>Check</u><u> </u><u>your </u><u>work</u><u>!</u>

(-6) × (-6+1)

(-6)× (-5)

30 = (-6)^2 -6

30 = 36-6

30= 30 ✓✓✓✓

That's how we determine that <em>this </em><em>is</em><em> </em><em>the</em><em> </em><em>corr</em><em>ect</em><em> </em><em>answe</em><em>r</em>

Hopefully this helps

5 0
3 years ago
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