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Simora [160]
3 years ago
14

Find the value of x.

Mathematics
2 answers:
Dimas [21]3 years ago
7 0

Answer:

x=3

Step-by-step explanation:

32/24=(6x+6)/(9x-9)

simplify by 8 in the left

4/3=6(x+1)/9(x-1)

simplify by 3 in the right

4/3=2(x+1)/3(x-1)

*3           *3

4=2(x+1)/(x-1)

(x+1)/(x-1)=4/2=2

so x+1=2(x-1)=2x-2

-x                     -x

1=x-2

+2    +2

3=x

so x=3

verify  (6*3+6)/(9*3-9)=32/24

24/18=32/24

simplify by 6  in the left

4/3=32/24

simplify by 8   in the right

4/3=4/3   TRUE

arlik [135]3 years ago
4 0

Answer:

or,6x+6=9x-9

or,6+9= 9x-6x

or,15=3x

or,15/3=X

therefore,X=5ans

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Step 1: evaluate f(x+h) and f(x)

We have

f(x+h) = -(x+h)^2+6(x+h)-5 = -(x^2+2xh+h^2)+6x+6h-5

= -x^2-2xh-h^2+6x+6h-5

And, of course,

f(x)=-x^2+6x-5

Step 2: evaluate f(x+h)-f(x)

f(x+h)-f(x)=-x^2-2xh-h^2+6x+6h-5-(-x^2+6x-5)=-2xh-h^2+6h

Step 3: evaluate (f(x+h)-f(x))/h

\dfrac{f(x+h)-f(x)}{h}=-2x-h+6

Step 4: evaluate the limit of step 3 as h->0

f'(x) = \displaystyle \lim_{h\to 0} \dfrac{f(x+h)-f(x)}{h}=-2x+6

So, we have

f'(1) = -2\cdot 1+6 = 4,\quad f'(2) = -2\cdot 2+6 = 2,\quad f'(3) = -2\cdot 3+6 = 0

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2/3(9a+18b)=6a+kb
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Answer:

4.) 12

Step-by-step explanation:

\frac{2}{3} (9a + 18b) = 6a + kb \\  \\  \implies \:  \frac{2}{3}  \times 9a +  \frac{2}{3}  \times 18b = 6a + kb \\  \\  \implies \: { 6a} + 12b = 6a + kb \\  \\  \implies \:  \cancel{ 6a} + 12b -  \cancel{ 6a} = kb \\  \\  \implies \:  12b = kb \\  \\ \implies \: k =  \frac{12\cancel b}{\cancel b}  \\  \\ \huge \implies \: k = 12

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Answer:

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Step-by-step explanation:

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