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lora16 [44]
3 years ago
11

On a city map, 2 inches represents 10 miles. The library and the bank are 5 inches apart on the map. What is the actual distance

between the library and the bank?
Mathematics
1 answer:
icang [17]3 years ago
6 0

Answer:

72

Step-by-step explanation:

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Find the solution set for the inequality x-10<10
Lelu [443]

Answer:

x<20

Step-by-step explanation:

x-10<10

add 10 to both sides

x<20

X can therefore be anything less than 20.

4 0
3 years ago
Jim and Sarah invited seven friends over for dinner. If each friend brought one guest how many people will be at the dinner excl
Vanyuwa [196]

16 people would be at the dinner because Jim and Sarah invited 7 friends and each friend brought 1 guest, so you do 7*2=14 and the 14 + Jim and Sarah=16 people.

7 0
3 years ago
Melinda spends $5 at each of the 14<br> stores she visits. How much money did she spend ?
Paha777 [63]

Answer:

$70

Step-by-step explanation:

5 dollars * 14 stores= $70

4 0
3 years ago
Read 2 more answers
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
Please help need answer for both questions
myrzilka [38]

Answer:

1. 32, 12

2. Enlargement

Step-by-step explanation:

Enlarged by a scale factor of 4

(Multiply all points by 4)

8 x 4 = 32

3 x 4 = 12

It is an enlargement because the points are larger than before.

5 0
3 years ago
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