After putting the value of y from the second equation to the first equation, the resultant equation is
.
GIven:
The equations are:

It is required to put the value of y from second equation to the first equation.
<h3>How to solve equations?</h3>
The value of y from the second equation is,

Now, put this value of y in the first equation as,

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is
.
For more details about equations, refer to the link:
brainly.com/question/2263981
Hi! So, the one that doesn't belong is a) y = 4x.
I think that this doesn't belong because every other option has a number after the variable (I forget the exact term for it but it's like +7, +4, and -1 for the rest of the options)
Please let me know how I can further help you :)
(
Answer:
John spent around $53
Step-by-step explanation:
The equation is 3x=160
Since the "x" is already by itself on one side, divide 160 by 3
160÷3=53.333⇒
Now if that's not the way IT CAN ALSO BE:
30x3+70=160! That means John spent $90
1.6 divided by x =4
we can exchange the 4 and the x
1.6 divided by 4 =x
.4 =x
-10d^2 + 11d - 2
To find this, distribute the - to 7d^2 - d - 6.
This will give you a new equation of:
-3d^2 + 10d - 8 -7d^2 + d + 6
Combine like terms to get the answer above.
Hope this helps!