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Tema [17]
2 years ago
11

Evaluate the expression. Assume that all the angles are in Quadrant I. (cos (arctan √3/7))

Mathematics
1 answer:
evablogger [386]2 years ago
3 0

Answer:

0.971

Step-by-step explanation:

Given the expression (cos (arctan √3/7)) which all lies in the first quadrant. Note that all the trigonometry identities (sin, cos and tan) are all positive in the first quadrant.

From the expression given

(cos (arctan √3/7)), we need to get the expression in parenthesis first.

Let y = (cos (arctan √3/7))

If u = arctan √3/7

Then y = cos(u) .... 1

Let's get the value of u first

u = arctan √3/7

u = arctan(0.2474)

u = 13.896°

Substituting u = 13.896° into equation 1, we will have;

y = cos(u)

y = cos13.896°

y = 0.971.

Hence the expression (cos(arctan√3/7)) is equivalent to 0.971

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Answer:

3

Step-by-step explanation:

Given the data: 7 6 5 9 3 4 7 9 5 8

INTERQUARTILE RANGE (IQR) = Q3 - Q1

Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9

Q3 = 0.75(n+1)th term

Q3 = 0.75(10 + 1) th term

Q3 = 0.75(11)th term = 8.25th term

Taking the 8th term = 8

Q1 = 0.25(11)th term = 2.75th

Taking the average of the 8th and 9th term:

(5 + 5) / 2 = 10/2 = 5

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3 years ago
PlZ ANSWER WILL GIVE BRAINLY
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Answer:

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Step-by-step explanation:

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3 years ago
Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds
Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

= total risk-(good risk+ medium risk)

= 11332-(7311+1182)

= 11332-8493

= 2839.

Poor risk = 2839

Probabilty that the ball choosen at random is not poor= 1 - probability that the ball is poor

Probability of poor = 2839/11332

Probabilty of poor= 0.2505

Probabilty that the ball choosen at random is not poor= 1- 0.2505

= 0.7495

To two decimal place= 0.75

3 0
3 years ago
Jessie works at a car manufacturing plant. One day she installed a total of 46 axles, 2 in each car she worked on. She wants to
shtirl [24]

Answer:

<h2>             23 cars</h2>

Step-by-step explanation:

total number of cars:    x

the total number of axles:    46

and the number of axles  installed per car:   2

2 axles in each car, then total instaled axles:  2•x

2•x = 46

x = 46÷2

x = 23

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3 years ago
In a standard deck of cards, what is the probability of drawing a red card or a face card? answer choices are in the form of a p
Orlov [11]

In a standard set of cards, the probability of drawing a red card or a face card is  73%

<h3>What is the probability?</h3>

In a standard deck of cards, there are 26 red cards. In that same deck, there will be 12 face cards.

The probability of picking either one is:

= (Number of face cards + Number of red cards) / Number of total cards

Solving gives:

= (12 + 26) / 52

= 38 / 52

= 73%

Find out more on probability at brainly.com/question/15812320

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4 0
1 year ago
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